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Message-ID: <003d01c566a2$93a498a0$42010180@nrg.cz>
From: =?iso-8859-2?B?WmRlbuxrIMhlcnZlbv0=?= <z.cerveny@atel-kladno.cz>
To: "=?iso-8859-2?Q?Ing._Josef_Navr=E1til?=" <j_navratil@karneval.cz>
References: <003101c56684$ee9beec0$298d190a@Pepa>
Subject: =?iso-8859-2?Q?Re:_kus_odpov=ECdi?=
Date: Wed, 1 Jun 2005 14:08:04 +0200
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( Navr=E1til - v=FDroba odpov=ECdi )

Zdenku, pod slovem a jeho v=FDznamem >krystal< si v=B9ichni lid=E9 =
vybavuj=ED   h m o t u  . M=E1lokdo pod pojmem >krystal< bude cht=EDt =
vid=ECt homoli =E8asoprostoru samotn=E9ho a absolutn=EC pr=E1zdn=E9ho. =
Tak=BEe j=E1 bych slovo krystal v duchu sou=E8asn=E9ho v=FDznamu =
nepou=BE=EDval. Slovo vakuum je lep=B9=ED ne=BE slovo krystal a tak bych =
je i odd=EClil Pojem vakuum jako takov=FD je s=E9manticky pr=E1zdn=FD, =
kde=BEto slovo krystal je spojeno s pravideln=FDm uspo=F8=E1d=E1n=EDm =
vnit=F8n=ED struktury, schopnost=ED p=F8en=E9=B9et kmity/zvuk (co=BE by =
mohlo b=FDt nap=F8. elm. z=E1=F8en=ED), permeabilita, permitivita,  a =
hlavn=EC typick=E9 poruchy - vakance (v m=F8=ED=BEce chyb=ECj=EDc=ED =
atom - to je mysl=EDm =E8=E1stice) a interstici=E1l (mimo m=F8=ED=BEku =
vtla=E8en=FD atom a to by mohla b=FDt anti=E8=E1stice) . To, =BEe z =
vakua "vyskakuje" hmota a antihmota =E8ili p=E1ry =E8=E1stic, je u=BE =
n=ECco jin=E9ho ... a ani toto nen=ED >krystal<. Hmota s antihmotou se =
odpuzuje elektromagneticky =E8ili jejich opa=E8n=E9 n=E1boje, v=BEdy =
jsou opa=E8n=E9 - t=EDm se li=B9=ED hmota od antihmoty, ale =
gravita=E8n=EC se oba k sob=EC p=F8itahuj=ED ( ! ), gravitace je st=E1le =
kladn=E1, ale tento p=F8=EDdavek do sou=E8tu je zanedbateln=FD. Dva =
elektrony ( se z=E1porn=FDm n=E1bojem ) se gravita=E8n=EC p=F8itahuj=ED, =
a sou=E8asn=EC se elektromagneticky odpuzuj=ED, Tyto =FA=E8inky se =
se=E8tou. A proto=BEe gravitace je mnoha=F8=E1dov=EC slab=B9=ED, tak =
lid=E9 i fyzikov=E9 kdy=BE mluv=ED o chov=E1n=ED dvou elektron=F9 =
vz=E1jemn=EC, tak gravitaci automaticky zanedb=E1vaj=ED. To plat=ED i o =
jin=FDch =E8=E1stic=EDch s n=E1boji.

Pouze ... kolik m=E1me =E8=E1stic co jsou si sami sob=EC =
anti=E8=E1stic=ED ? foton foton mysl=EDm nen=ED =E8=E1stice v prav=E9m =
slova smyslu (lokalizovan=E1) je to kmit=E1n=ED /vln=ECn=ED =
vakua/"krystalu", kter=E9 se m=F9=BEe projevit nap=F8. v n=ECjak=E9 =
nehomogenn=ED  =E8=E1sti vakua - pak mu =F8=EDk=E1me foton -  nap=F8. =
kreac=ED p=E1ru  V krystalov=E9m pohledu to lze jednodu=B9e vysv=ECtlit =
tak, =BEe kmit=E1n=ED bylo tak intenzivn=ED, =BEe vyrazilo n=ECkter=FD =
(m=E9n=EC v=E1zan=FD) atom z m=F8=ED=BEkov=E9 pozice do mezipozice. Nebo =
nap=F8. dva chyb=ECj=EDc=ED atomy v m=F8=ED=BEce deformuj=ED strukturu =
krystalu tak, =BEe je v=FDhodn=ECj=B9=ED aby byly co nejbl=ED=BEe - =
p=F8itahuj=ED se.. atp.. . ?=20

   Ale co je zaj=EDmav=E9, je to, =BEe "=BEivot" anti=E8=E1stice je =
kr=E1tk=FD, velmi kr=E1tk=FD a v=BEdy. =AEivot anti=E8=E1stice je =
kr=E1tk=FD proto, =BEe p=F8evl=E1daj=ED =E8=E1stice, d=F8=EDve nebo =
pozd=ECji na ni anti=E8=E1stice naraz=ED=ED. Mysl=EDm, v pr=E1zdn=E9m =
vakuu by se pozitron pohyboval pr=E1v=EC tak dlouho jako elektron.. =20

=20

To jsou jen =FAtr=BEkovit=E9 reakce, netvrd=EDm, =BEe m=E1m v=B9echno =
promy=B9leno ale takov=FDto model m=EC p=F8itahuje, p=F8ijde m=EC =
mnohokr=E1t "p=F8irozen=ECj=B9=ED/elegantn=ECj=B9=ED" ne=BE =
dvan=E1ctidimenzion=E1ln=ED struny. Je mi jasn=E9 =BEe je pro =
v=ECt=B9inu lid=ED zcela nestraviteln=FD, -douf=E1m sis' vzal Kinedryl - =
ale snad to m=F9=BEe n=ECkoho p=F8inutit zap=F8em=FD=B9let o =
probl=E9mech trochu z jin=E9ho =FAhlu..



Zdrav=ED Z.=C8.

  ----- Original Message -----=20
  From: Ing. Josef Navr=E1til=20
  To: Zden=ECk =C8erven=FD=20
  Sent: Wednesday, June 01, 2005 10:35 AM
  Subject: kus odpov=ECdi



  ing. Josef Navr=E1til, Kosmonaut=F9 154, D=EC=E8=EDn  405 01,
  e-mail : j_navratil@karneval.cz=20
  http://www.volny.cz/j_navratil



        ________ Information from NOD32 ________
        This message was checked by NOD32 Antivirus System for Linux =
Mail Server.
        http://www.nod32.com=20


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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Diso-8859-2">
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<STYLE></STYLE>
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<BODY bgColor=3D#ffffff>
<DIV>
<P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
style=3D"FONT-SIZE: 10pt; FONT-FAMILY: Arial">( Navr=E1til &#8211; =
v=FDroba odpov=ECdi=20
)<?xml:namespace prefix =3D o ns =3D =
"urn:schemas-microsoft-com:office:office"=20
/><o:p></o:p></SPAN></P>
<P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
style=3D"FONT-SIZE: 10pt; FONT-FAMILY: Arial">Zdenku, pod slovem a jeho =
v=FDznamem=20
&gt;krystal&lt; si v=B9ichni lid=E9 vybavuj=ED<SPAN=20
style=3D"mso-spacerun: yes">&nbsp;&nbsp; </SPAN>h m o t u<SPAN=20
style=3D"mso-spacerun: yes">&nbsp; </SPAN>. M=E1lokdo pod pojmem =
&gt;krystal&lt;=20
bude cht=EDt vid=ECt homoli =E8asoprostoru samotn=E9ho a absolutn=EC =
pr=E1zdn=E9ho. Tak=BEe j=E1=20
bych slovo krystal v&nbsp;duchu sou=E8asn=E9ho v=FDznamu nepou=BE=EDval. =
Slovo vakuum je=20
lep=B9=ED ne=BE slovo krystal a tak bych je i odd=EClil <SPAN =
style=3D"COLOR: red">Pojem=20
vakuum jako takov=FD je s=E9manticky pr=E1zdn=FD, kde=BEto slovo krystal =
je spojeno=20
s&nbsp;pravideln=FDm uspo=F8=E1d=E1n=EDm vnit=F8n=ED struktury, =
schopnost=ED p=F8en=E9=B9et kmity/zvuk=20
(co=BE by mohlo b=FDt nap=F8. elm. z=E1=F8en=ED),&nbsp;permeabilita, =
permitivita, &nbsp;a=20
hlavn=EC typick=E9 poruchy &#8211; vakance (v m=F8=ED=BEce =
chyb=ECj=EDc=ED atom &#8211; to je mysl=EDm=20
=E8=E1stice) a interstici=E1l (mimo m=F8=ED=BEku vtla=E8en=FD atom a to =
by mohla b=FDt=20
anti=E8=E1stice) </SPAN>. To, =BEe z&nbsp;vakua &#8222;vyskakuje&#8220; =
hmota a antihmota =E8ili=20
p=E1ry =E8=E1stic, je u=BE n=ECco jin=E9ho ... a ani toto nen=ED =
&gt;krystal&lt;. Hmota=20
s&nbsp;antihmotou se odpuzuje elektromagneticky =E8ili jejich opa=E8n=E9 =
n=E1boje, v=BEdy=20
jsou opa=E8n=E9 &#8211; t=EDm se li=B9=ED hmota od antihmoty, ale =
gravita=E8n=EC se oba k&nbsp;sob=EC=20
p=F8itahuj=ED ( ! ), gravitace je st=E1le kladn=E1, ale tento =
p=F8=EDdavek do sou=E8tu je=20
zanedbateln=FD. Dva elektrony ( se z=E1porn=FDm n=E1bojem ) se =
gravita=E8n=EC p=F8itahuj=ED, a=20
<U>sou=E8asn=EC</U> se elektromagneticky odpuzuj=ED, Tyto =FA=E8inky se =
se=E8tou. A proto=BEe=20
gravitace je mnoha=F8=E1dov=EC slab=B9=ED, tak lid=E9 i fyzikov=E9 =
kdy=BE mluv=ED o chov=E1n=ED dvou=20
elektron=F9 vz=E1jemn=EC, tak gravitaci automaticky zanedb=E1vaj=ED. To =
plat=ED i o jin=FDch=20
=E8=E1stic=EDch s&nbsp;n=E1boji.<o:p></o:p></SPAN></P>
<P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
style=3D"FONT-SIZE: 10pt; FONT-FAMILY: Arial">Pouze ... kolik m=E1me =
=E8=E1stic co jsou=20
si sami sob=EC anti=E8=E1stic=ED ? foton <SPAN style=3D"COLOR: =
red">foton mysl=EDm nen=ED=20
=E8=E1stice v&nbsp;prav=E9m slova smyslu&nbsp;(lokalizovan=E1) je to =
kmit=E1n=ED /vln=ECn=ED=20
vakua/&#8220;krystalu&#8220;, kter=E9 se m=F9=BEe projevit nap=F8. =
v&nbsp;n=ECjak=E9 nehomogenn=ED <SPAN=20
style=3D"mso-spacerun: yes">&nbsp;</SPAN>=E8=E1sti vakua - pak mu =
=F8=EDk=E1me foton=20
-&nbsp;</SPAN><SPAN style=3D"mso-spacerun: yes">&nbsp;</SPAN><SPAN=20
style=3D"COLOR: red">nap=F8. kreac=ED p=E1ru <SPAN=20
style=3D"mso-spacerun: yes">&nbsp;</SPAN>V&nbsp;krystalov=E9m pohledu to =
lze=20
jednodu=B9e vysv=ECtlit tak, =BEe kmit=E1n=ED bylo tak intenzivn=ED, =
=BEe vyrazilo n=ECkter=FD=20
(m=E9n=EC v=E1zan=FD) atom z&nbsp;m=F8=ED=BEkov=E9 pozice do mezipozice. =
Nebo nap=F8. dva=20
chyb=ECj=EDc=ED atomy v&nbsp;m=F8=ED=BEce deformuj=ED strukturu krystalu =
tak, =BEe je v=FDhodn=ECj=B9=ED=20
aby byly co nejbl=ED=BEe &#8211; p=F8itahuj=ED se.. atp.&#8230; .</SPAN> =
? <o:p></o:p></SPAN></P>
<P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
style=3D"FONT-SIZE: 10pt; FONT-FAMILY: Arial"><SPAN=20
style=3D"mso-spacerun: yes">&nbsp;&nbsp; </SPAN>Ale co je zaj=EDmav=E9, =
je to, =BEe=20
&#8222;=BEivot&#8220; anti=E8=E1stice je kr=E1tk=FD, velmi kr=E1tk=FD a =
v=BEdy. <SPAN=20
style=3D"COLOR: red">=AEivot anti=E8=E1stice je kr=E1tk=FD proto, =BEe =
p=F8evl=E1daj=ED =E8=E1stice,=20
d=F8=EDve nebo pozd=ECji na ni anti=E8=E1stice naraz=ED=ED. Mysl=EDm, =
v&nbsp;pr=E1zdn=E9m vakuu by=20
se pozitron pohyboval pr=E1v=EC tak dlouho jako elektron..</SPAN> <SPAN=20
style=3D"mso-spacerun: yes">&nbsp;</SPAN><o:p></o:p></SPAN></P>
<P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
style=3D"FONT-SIZE: 10pt; FONT-FAMILY: =
Arial"><o:p>&nbsp;</o:p></SPAN></P>
<P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
style=3D"FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">To jsou jen =
=FAtr=BEkovit=E9=20
reakce, netvrd=EDm, =BEe m=E1m v=B9echno promy=B9leno ale takov=FDto =
model m=EC p=F8itahuje,=20
p=F8ijde m=EC&nbsp;mnohokr=E1t =
&#8222;p=F8irozen=ECj=B9=ED/elegantn=ECj=B9=ED&#8220; ne=BE =
dvan=E1ctidimenzion=E1ln=ED=20
struny. Je mi jasn=E9 =BEe je pro v=ECt=B9inu lid=ED zcela =
nestraviteln=FD, -douf=E1m sis&#8217;=20
vzal Kinedryl &#8211; ale snad to&nbsp;m=F9=BEe n=ECkoho p=F8inutit =
zap=F8em=FD=B9let o probl=E9mech=20
trochu z&nbsp;jin=E9ho =FAhlu..</SPAN></P>
<P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
style=3D"FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: =
Arial"></SPAN>&nbsp;</P>
<P class=3DMsoNormal style=3D"MARGIN: 0cm 0cm 0pt"><SPAN=20
style=3D"FONT-SIZE: 10pt; COLOR: red; FONT-FAMILY: Arial">Zdrav=ED=20
Z.=C8.</SPAN></P></DIV>
<BLOCKQUOTE=20
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
  <DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
  <DIV=20
  style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
  <A title=3Dj_navratil@karneval.cz =
href=3D"mailto:j_navratil@karneval.cz">Ing.=20
  Josef Navr=E1til</A> </DIV>
  <DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
title=3Dz.cerveny@atel-kladno.cz=20
  href=3D"mailto:z.cerveny@atel-kladno.cz">Zden=ECk =C8erven=FD</A> =
</DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Wednesday, June 01, 2005 =
10:35=20
  AM</DIV>
  <DIV style=3D"FONT: 10pt arial"><B>Subject:</B> kus odpov=ECdi</DIV>
  <DIV><BR></DIV>
  <DIV>&nbsp;</DIV>
  <DIV><FONT face=3DArial size=3D2>ing. Josef Navr=E1til, Kosmonaut=F9 =
154, D=EC=E8=EDn&nbsp;=20
  405 01,<BR>e-mail : <A=20
  href=3D"mailto:j_navratil@karneval.cz">j_navratil@karneval.cz</A> =
<BR><A=20
  =
href=3D"http://www.volny.cz/j_navratil">http://www.volny.cz/j_navratil</A=
><BR></FONT></DIV><BR><BR>
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      <TD style=3D"COLOR: #000000"><STRONG>________ Information from =
NOD32=20
        ________</STRONG><BR>This message was checked by NOD32 Antivirus =
System=20
        for Linux Mail Server.<BR><A style=3D"COLOR: #0000dd"=20
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